How to draw IF5 Lewis Structure?

The Iodine pentafluoride chemical formula is IF5. Drawing IF5 Lewis Structure is very easy to by using the following method. Here in this post, we described step by step method to construct IF5 Lewis Structure. The Iodine and fluorine elements come as the member of the halogen family group from the periodic table. The valence electrons in Iodine and fluorine are seven. The branch of halogen chemistry is used to make chemicals reagents for fluorination reactions.

Key Points To Consider When Drawing The IF5 Electron Dot Structure

A three-step approach for drawing the IF5 Lewis structure can be used. The first step is to sketch the Lewis structure of the IF5 molecule, to add valence electrons around the Iodine atom; the second step is to add valence electrons to the five fluorine atoms, and the final step is to combine the step1 and step2 to get the IF5 Lewis Structure.

The IF5 Lewis structure is a diagram that illustrates the number of valence electrons and bond electron pairs in the IF5 molecule. The geometry of the IF5 molecule can then be predicted using the Valence Shell Electron Pair Repulsion Theory (VSEPR Theory), which states that molecules will choose the IF5 geometrical shape in which the electrons have from one another.

Finally, you must add their bond polarities to compute the strength of the five I-F bonds (dipole moment properties of the IF5 molecule). The Iodine-fluorine bonds in Iodine pentafluoride(IF5), for example, are polarised toward the more electronegative fluorine in IF5 molecule, and because both bonds have the same size and are located around five fluorine terminals of the square pyramidal with one lone pair (in total two-electrons) on the Iodine atom, their sum of dipole moment is nonzero due to the IF5 molecule’s bond dipole moment and more electron polarity to the fluorine atoms. Because each five I-F bonds polarity not canceled each other in the IF5 molecule. The Penta fluoro Iodine or Iodine pentafluoride(IF5) molecule is classified as a polar molecule.

How to draw IF5 Lewis Structure?

The molecule of Iodine pentafluoride (with square pyramidal molecular geometry) is tilted, the bond angles between Iodine and fluorine are 90 degrees. It has a difference in electronegativity values between Iodine and fluorine atoms, with central Iodine’s pull being less than terminal fluorine’s in the IF5 molecule. But they not canceled each other due to the asymmetrical molecular geometry of the IF5 molecule.

As a result, it has the nonzero dipole moment. The IF5 molecule has a nonzero dipole moment due to an unequal charge distribution of negative and positive charges. But both these atoms fall on the halogen family group. The fluorine atom is a more electronegative value than Iodine in the IF5 molecule. The IF5 molecule has the net dipole moment.

Molecules can be classified as polar or nonpolar. The molecule polar behaves in a different manner as compared to nonpolar.

Overview: IF5 Lewis Structure

The central atom is Iodine, which is bordered on five terminals with fluorine atoms( in square pyramidal), and one lone pair on the central in the square pyramidal geometry. Iodine has seven outermost valence electrons, indicating that it possesses seven electrons in its outermost shell, whereas fluorine also has seven valence electrons in its outermost shell. To complete the octet of the Iodine and fluorine atoms requires one valence electron on each of their outermost shell.

Five fluorine atoms establish covalent connections with the central Iodine atom as a result, leaving the Iodine atom with two lone pairs. There are two lone pairs of electrons on the Iodine central atom that resists the bond pairs of the five I-F. According to VSEPR theory, the I-F bond pairs polarity lead the IF5 molecule to take on the square pyramidal geometry structure.

The IF5 molecule’s five I-F bonds are arranged in unsymmetrical polarity order around the square pyramidal molecular geometry, giving rise to the IF5 molecular shape. The IF5 molecule has a square pyramidal molecular geometry because there is electrical repulsion between the lone pairs of electrons in fluorine and five bond pairs(I-F) of the IF5 molecule.

Lewis structure of IF5 has dot electron representative structure. Valence electrons of atoms undergo orbitals mixing in the chemical reactions, gives new types of molecular species. The molecule is nothing but a bundle of valence electrons from the atoms. But it is converted to bond pairs and lone pairs in the molecular structure.

Electronegative value Difference Calculation of IF5 Molecule:

Iodine and Fluorine Electronegative difference in IF5:

The Iodine atom has an electronegativity of 2.66, while fluorine has an electronegativity of 3.98 in the IF5 molecule. The difference in electronegativity of Iodine and fluorine can be estimated using the method below.

The electronegative value difference between Iodine and fluorine in IF5 molecule

Electronegativity value of Iodine = 2.66

Electronegativity value of fluorine= 3.98

Difference of electronegativity value between Iodine and fluorine in IF5 molecule = 3.98 – 2.66=1.32Electronegativity difference between I-F bond calculation of IF5 molecule.

The electronegative difference between Iodine and fluorine is greater than 0.5. This indicated the bond polarity moves near to polar nature. I-F bond polarity in the IF5 molecule is polar.

Because of this difference in electronegativity of Iodine and fluorine atoms, the IF5 molecule’s I-F bond becomes polar. The total net dipole moment of the IF5 molecule is nonzero due to the no cancellation of the bond dipole moment in the square pyramidal geometry. The electronegativity of an atom is the strength with which it may attract bound electron pairs to its side. The polarity of IF5 is discussed in our previous post.

As a result, the I-F bond’s dipole moment is high due to the polarization of the bonds and one lone pair of electrons on Iodine, and all I-F bonds’ dipoles are arranged in the asymmetrical IF5 molecular geometry. The IF5 molecule has a total dipole moment.

The electron dot structure of the IF5 molecule is also known as the IF5 Lewis structure. It determines the number of outermost valence electrons as well as the electrons engaged in the IF5 molecule’s bond formation. The outermost valence electrons of the IF5 molecule must be understood while considering the Lewis structure of the molecule.

The Iodine atom is the middle element in IF5 molecular geometry, with seven electrons in its outermost valence electron shell, whereas the fluorine atom has seven electrons in its outermost valence electron shell. The fluorine atom has seven valence electrons.

The IF5 has a total of 42 valence electrons as a result of the foregoing above-said reasoning. With the core central Iodine atom, the five terminals with five fluorine atoms form covalent bonds, leaving the Iodine atom with one lone pair in the middle of square pyramidal geometry.

Because lone pair on the terminal fluorine atom creates interaction with I-F bond pairs(but it is negligible). The bond angle of the F-I-F bond in the square pyramidal molecular geometry is approximately 82 degrees. This angle is less than the ClF5 molecule bond angle. The I-F bond length is 184 to 187 pm(picometer).

To sketch the IF5 Lewis structure by following these instructions:

Step-1: IF5 Lewis dot Structure by counting valence electrons on the Iodine atom

To calculate the valence electron of each atom in IF5, look for its periodic group from the periodic table. The halogen group families, which are the 17th group in the periodic table, are both made up of Iodine and fluorine atoms. In their outermost shells, fluorine and Iodine have seven valence electrons.

Calculate the total number of valence electrons in the IF5 molecule’s outermost valence shell. The first step is to determine how many electrons are in the IF5 Lewis structure’s outermost valence shell. An electron in an atom’s outermost shell is known as a valence electron. It is represented by dots in the IF5 Lewis diagram. The IF5 molecule’s core Iodine atom can be represented as follows:

Total outermost valence shell electron of Iodine atom in IF5= 7

Total outermost valence shell electron of fluorine atom in IF5= 7

The IF5 molecule has one central Iodine and five fluorine atoms. Then the total outermost valence shell electrons can be calculated as follows

∴ Total outermost valence shell electrons available for IF5 Lewis structure( dot structure) = 7+5*7=42 valence electrons  in IF5.  

calculation of total valence electron of IF5 molecule

Choose the atom with the least electronegative value atom and insert it in the center of the molecular geometry of IF5. We’ll choose the least electronegative value atom in the IF5 molecule to place in the center of the IF5 Lewis structure diagram in this phase. The electronegativity value in periodic groups grows from left to right in the periodic table and drops from top to bottom.

How to draw IF5 Lewis Structure?

The first step is to put seven valence electrons around the Iodine atom as given in the figure.

Step-2: Lewis Structure of IF5 for counting valence electrons around the terminal fluorine atoms

As a result, Iodine is the fourth atom in the periodic table’s halogen family group. Fluorine is the first member of the halogen family. The electronegative value of the fluorine atom is higher than that of the Iodine atom in the IF5 molecule. Furthermore, fluorine has a seven electrons limit since Iodine is the less electronegative element in the IF5 molecule.

n the IF5 Lewis structure diagram, the Iodine atom can be the center atom of the molecule. As a result, central Iodine in the IF5 Lewis structure, with all five fluorine atoms arranged in square pyramidal geometry.

How to draw IF5 Lewis Structure?

Add valence electrons around the fluorine atom, as given in the figure.

Step-3: Lewis dot Structure for IF5 generated from step-1 and step-2

Connect the exterior and core central atom of the IF5 molecule with five single I-F bonds. In this stage, use five fluorine atoms on the outside of the IF5 molecule to the central Iodine atom in the middle.

Count how many electrons from the outermost valence shell have been used in the IF5 structure so far. Each I-F bond carries two electrons because each Iodine atom is connected to five fluorine atoms by five I-F bonds. Bond pairings of I-F are what they’re called.

So, out of the total of 42 valence electrons available for the IF5 Lewis structure, we used 10 electrons for the IF5 molecule’s five I-F bonds. The IF5 molecule has one lone pair of electrons in the central Iodine atom.

Place the valence electrons in the I-F bond pairs starting with the core Iodine, five fluorine atoms in the IF5 molecule. In the IF5 Lewis structure diagram, we always begin by introducing valence electrons from the central Iodine atom(in step1). As a result, wrap around the central Iodine atom’s bond pair valence electrons first (see figure for step1).

The Iodine atom in the molecule gets only ten electrons around its molecular structure. This central Iodine atom is extra octet stable. But it has one lone pair. Iodine(Br2) is blue gas in nature. when Iodine acted as chlorinating agent, it is used as a chemical reagent. But IF5 is used as a fluorinating agent in organic chemistry.

Iodine requires 12 electrons in its outermost valence shell to complete the molecular extra octet stability, 10 electrons bond pairs in five I-F bonds. Then lone pairs of electrons on the fluorine atoms of the IF5 molecule are placed in a square pyramidal geometry. Iodine already shares ten electrons to the five I-F bonds. Then place the valence electron in the fluorine atoms, it placed around seven electrons on each atom(step-2). 30 valence electrons were placed around fluorine atoms as lone pairs of electrons.

How to draw IF5 Lewis Structure?

We’ve positioned 30 electrons around the terminal fluorine atoms(step-3), which is represented by a dot, in the IF5 molecular structure above. The Iodine atom completes its molecular extra octet stability in the IF5 molecule because it possesses ten electrons in its (five I-F) bond pairs with five fluorine in the outermost valence shell.

Count how many outermost valence shell electrons have been used so far using the IF5 Lewis structure. Five electron bond pairs are shown as dots in the IF5 chemical structure, whereas five single bonds each contain two electrons. The outermost valence shell electrons of the IF5 molecule(bond pairs) are ten as a result of the calculation.

So far, we’ve used 42 of the IF5 Lewis structure’s total 42 outermost valence shell electrons. One lone pair of electrons on the Iodine atom in the square pyramidal of the IF5 molecule.

Complete the middle Iodine atom stability and, if necessary, apply a covalent bond. The central Iodine atom undergoes extra octet stability(due to one lone pair of electrons).

The core atom in the IF5 Lewis structure is Iodine, which is bonded to the five fluorine atoms by single bonds (five I-F). With the help of five single bonds, it already shares ten electrons. As a result, the Iodine follows the extra octet rule and has ten electrons surrounding it on the five terminals of the IF5 molecule’s square pyramidal geometry.

How to calculate the formal charge on Iodine and fluorine atoms in IF5 Lewis Structure?

Calculating formal charge on the Iodine of IF5 molecule:

The formal charge on the IF5 molecule’s Iodine central atom often corresponds to the actual charge on that Iodine central atom. In the following computation, the formal charge will be calculated on the central Iodine atom of the IF5 Lewis dot structure.

To calculate the formal charge on the central Iodine atom of the IF5 molecule by using the following formula:

The formal charge on the Iodine atom of IF5 molecule= (V. E(Br)– L.E(Br) – 1/2(B.E))

V.E (Br) = Valence electron in a Iodine atom of IF5 molecule

L.E(Br) = Lone pairs of an electron in the Iodine atom of the IF5 molecule.

B.E = Bond pair electron in Br atom of IF5 molecule

calculation of formal charge on Iodine atom in IF5 molecule

The Iodine core atom (five single bonds connected to five fluorine atoms ) of the IF5 molecule has seven valence electrons, one lone pair of electrons(two electrons), and ten bonding pairing valence electrons. Put these values for the Iodine atom in the formula above.

Formal charge on Iodine atom of IF5 molecule = (7- 2-(10/2)) =0

In the Lewis structure of IF5, the formal charge on the central Iodine atom is zero.

Calculating formal charge on the fluorine of IF5 molecule:

The formal charge on the IF5 molecule’s fluorine terminal atom often corresponds to the actual charge on that fluorine terminal atom. In the following computation, the formal charge will be calculated on the terminal fluorine atom of the IF5 Lewis dot structure.

To calculate the formal charge on the terminal fluorine atom of the IF5 molecule by using the following formula:

The formal charge on the fluorine atom of IF5 molecule= (V. E(F)– L.E(F) – 1/2(B.E))

V.E (F) = Valence electron in a fluorine atom of IF5 molecule

L.E(F) = Lone pairs of an electron in the fluorine atom of the IF5 molecule.

B.E = Bond pair electron in F atom of IF5 molecule

calculation of formal charge on fluorine atom in IF5 molecule

The fluorine terminal atom of the IF5 molecule has seven valence electrons, three lone pairs of electrons(six electrons), and two bonding pairing valence electrons. Put these values for the fluorine atom in the formula above.

Formal charge on fluorine atom of IF5 molecule = (7- 6-(2/2)) =0

In the Lewis structure of IF5, the formal charge on the terminal fluorine atom is zero.

Summary:

In this post, we discussed the method to construct the IF5 Lewis structure. First, the valence electrons are placed around the Iodine atom. Second, place the valence electron on the fluorine atoms. Finally, when we combined the first and second steps. It gives IF5 Lewis structure. Need to remember that, if you follow the above-said method, you can construct molecular dot structure very easily.

What is ClF5 Molecular geometry?

ClF5 Molecular geometry is an electronic structural representation of molecules.

What is the molecular notation for ClF5 molecule?

ClF5 molecular notation is AX5N1.

The polarity of the molecules

The polarity of the molecules are listed as follows

Lewis Structure and Molecular Geometry

Lewis structure and molecular geometry of molecules are listed below

External References

Information on iodine pentafluoride(IF5)

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